document.write( "Question 877287: Please help me solve for x and y\r
\n" ); document.write( "\n" ); document.write( "4y+3y=50 and x^2+y^2=100
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Algebra.Com's Answer #529264 by Alan3354(69443)\"\" \"About 
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Please help me solve for x and y\r
\n" ); document.write( "\n" ); document.write( "4y+3y=50
\n" ); document.write( "x^2+y^2=100
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\n" ); document.write( "7y = 50
\n" ); document.write( "y = 50/7
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\n" ); document.write( "x^2 + (50/7)^2 = 100
\n" ); document.write( "x^2 = 100 - 2500/49 = 2400/49
\n" ); document.write( "x = 20sqrt(6)/7
\n" ); document.write( "x = -20sqrt(6)/7
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