document.write( "Question 877244: Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = -1 \n" ); document.write( "
Algebra.Com's Answer #529250 by nerdybill(7384)\"\" \"About 
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Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = -1
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\n" ); document.write( "vertex is mid-way between the focus and directrix:
\n" ); document.write( "vertex: (-5,2)
\n" ); document.write( "standard form of a vertical parabola
\n" ); document.write( "(x – h)^2 = 4p(y – k)
\n" ); document.write( "(x – (-5))^2 = 4p(y – 2)
\n" ); document.write( "(x + 5)^2 = 4p(y – 2)
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\n" ); document.write( "p is the distance between the vertex and either the focus or directrix:
\n" ); document.write( "p = 3
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\n" ); document.write( "so our final equation is:
\n" ); document.write( "(x + 5)^2 = 4*3(y – 2)
\n" ); document.write( "(x + 5)^2 = 12(y – 2)\r
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