document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=877223>Question 877223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help not sure how to go about answering this problem,  here goes: A business man invest a total of $13900 into two businesses A and B at the simple interest rate of 14%  per annum and 11% per annum respectively.  If the total amount of simple interest for 2 years was $3508, what was the amount invested in business B<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529249 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529249\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A business man invest a total of $13900 into two businesses A and B at the simple interest rate of 14% per annum and 11% per annum respectively.<BR>\n" );
document.write( " If the total amount of simple interest for 2 years was $3508, what was the amount invested in business B.<BR>\n" );
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document.write( "Let a = amt invested at 14% (.14)<BR>\n" );
document.write( "Let b = amt invested at 11% (.11)<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "a + b = 13900<BR>\n" );
document.write( "b = (13900-a); use this form for substitution<BR>\n" );
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document.write( "\" If the total amount of simple interest for 2 years was $3508, \"<BR>\n" );
document.write( "therefore (remember it's 2yrs simple interest)<BR>\n" );
document.write( "2(.14a + .11b) = 3508<BR>\n" );
document.write( "Divide both sides by 2<BR>\n" );
document.write( ".14a + .11b = 1754<BR>\n" );
document.write( "Substitute (13900-a) for b<BR>\n" );
document.write( ".14a + .11(13900-a) = 1754<BR>\n" );
document.write( ".14a + 1529 - .11a = 1754<BR>\n" );
document.write( ".14a - .11a = 1754 - 1529<BR>\n" );
document.write( ".03a = 225<BR>\n" );
document.write( "a = 225/.03<BR>\n" );
document.write( "a = 7500 invested at 14%<BR>\n" );
document.write( ";<BR>\n" );
document.write( "\"what was the amount invested in business B\"<BR>\n" );
document.write( "b = 13900 - 7500<BR>\n" );
document.write( "b = $6400 invested at 11%<BR>\n" );
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document.write( "Check this for yourself, find the interest of each using I - PRT<BR>\n" );
document.write( "See that they add up to 3508 </SPAN>\n" );
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