document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=877223>Question 877223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help not sure how to go about answering this problem,  here goes: A business man invest a total of $13900 into two businesses A and B at the simple interest rate of 14%  per annum and 11% per annum respectively.  If the total amount of simple interest for 2 years was $3508, what was the amount invested in business B<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529247 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be amount invested in business A and y amount invested in business B, then<BR>\n" );
document.write( "x + y = 13900<BR>\n" );
document.write( "now I = p*r*t<BR>\n" );
document.write( "3508 = (.14x + .11y) * 2<BR>\n" );
document.write( "solve first equation for x<BR>\n" );
document.write( "x = 13900 - y<BR>\n" );
document.write( "substitute for y in second equation<BR>\n" );
document.write( "3508 = (.14(13900-y) + .11y) * 2<BR>\n" );
document.write( "divide both sides of = by 2<BR>\n" );
document.write( "1754 = (1946 -.14y + .11y)<BR>\n" );
document.write( "1754 = (1946 -.03y)<BR>\n" );
document.write( ".03y =  192<BR>\n" );
document.write( "y = 6400<BR>\n" );
document.write( "$6400 invested in business B<BR>\n" );
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