document.write( "Question 73912: How many pounds of hamburger that costs $1.10 per pound must be mixed with 50 pounds of hamburger that costs $1.80 per pound to make a mixture that costs $1.30 per pound? \n" ); document.write( "

Algebra.Com's Answer #52920 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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How many pounds of hamburger that costs $1.10 per pound must be mixed with 50 pounds of hamburger that costs $1.80 per pound to make a mixture that costs $1.30 per pound?
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\n" ); document.write( "Let x = number of lbs of $1.10 hamburger
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\n" ); document.write( "We know that there is 50 lbs of the $1.80 hamburger
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\n" ); document.write( "Therefore the resulting amt will be (x + 50)
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\n" ); document.write( "The equation:
\n" ); document.write( "1.1x + 1.8(50) = 1.3(x + 50)
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\n" ); document.write( "1.1x + 90 = 1.3x + 65
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\n" ); document.write( "1.1x - 1.3x = 65 - 90
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\n" ); document.write( "-.2x = -25
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\n" ); document.write( "x = -25/-.2
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\n" ); document.write( "x = +125 lbs of $1.10 stuff required
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\n" ); document.write( "Check:
\n" ); document.write( "1.1(125) + 1.8(50) = 1.3(125 + 50)
\n" ); document.write( "137.5 + 90 = 1.3(175)
\n" ); document.write( "227.5 = 227.5 proves our solution
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