document.write( "Question 877071: Two years ago a man was six times as old as his daughter. In 18 years he will be twice as old as his daughter. Determine their present ages. \n" ); document.write( "
Algebra.Com's Answer #529195 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
let m = man's present age
\n" ); document.write( "let d - daughter's
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement, simplify as much as possible
\n" ); document.write( ":
\n" ); document.write( " Two years ago a man was six times as old as his daughter.
\n" ); document.write( "m- 2 = 6(d-2)
\n" ); document.write( "m - 2 = 6d - 12
\n" ); document.write( "m = 6d - 12 + 2
\n" ); document.write( "m = 6d - 10
\n" ); document.write( ":
\n" ); document.write( "In 18 years he will be twice as old as his daughter.
\n" ); document.write( "m + 18 = 2(d+18)
\n" ); document.write( "m + 18 = 2d + 36
\n" ); document.write( "m = 2d + 36 - 18
\n" ); document.write( "m = d + 18
\n" ); document.write( "From the 1st equation, replace m with (6d-10)
\n" ); document.write( "6d - 10 = 2d + 18
\n" ); document.write( "6d - 2d = 18 + 10
\n" ); document.write( "4d = 28
\n" ); document.write( "d = 28/4
\n" ); document.write( "d = 7 yrs is the daughter's age
\n" ); document.write( "Find Dad's age
\n" ); document.write( "m = 6(7) - 10
\n" ); document.write( "m = 42 - 10
\n" ); document.write( "m = 32 yrs is Dad's age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solutions in the statement:
\n" ); document.write( "\"In 18 years he will be twice as old as his daughter.\"
\n" ); document.write( "32 + 18 = 2(7 + 18)
\n" ); document.write( "50 = 2(25)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );