document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73600>Question 73600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a bacteria culture started with a count of 720 at 8am and after t hours is expected to grow to f(t)=720(3/2)^t. estimate number of bacteria in culture at 11am the same day? Here is what I got f(3)=720(3/2)^3=? Am I on track? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52919 by </B><A HREF=/tutors/aboutme.mpl?userid=tazoftroy><B>tazoftroy(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tazoftroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yeah, just plug in 3 for t to get a count of 2430. </SPAN>\n" );
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