document.write( "Question 877118: from a group of 5 boys and 4 girls, a committee of 4 must be selected. Each committee must have at least one boy and at least one girl. How many ways can this be done?
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Algebra.Com's Answer #529184 by Edwin McCravy(20055)\"\" \"About 
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document.write( "The answer would be C(9,4) = 126 committees if there were no restrictions.\r\n" );
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document.write( "However we must subtract the number of committees cosisting of all boys and\r\n" );
document.write( "the number of committees consisting of all girls.\r\n" );
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document.write( "There are C(5,4) = 5 committes of all boys.  (5 ways to leave one boy out)\r\n" );
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document.write( "There is C(4,4) = 1 committee of all girls.  (1 way to choose all 4 girls)\r\n" );
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document.write( "Answer 126 - 5 - 1 = 120 ways.\r\n" );
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document.write( "Edwin
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