document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=877111>Question 877111</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this problem ASAP, I don't understand any of it at all. [Use the recursive rule to find the third term in the sequence. a_1=6 and a_n = a_n-1 + 3   ] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529174 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are given a_1 = 6 and<BR>\n" );
document.write( "a_n = a_n-1 + 3<BR>\n" );
document.write( "a_3 = a_2 + 3<BR>\n" );
document.write( "Now a_2 = a_1 + 3 = 6 + 3 = 9<BR>\n" );
document.write( "a_3 = a_2 + 3 = 9 + 3 = 12<BR>\n" );
document.write( " </SPAN>\n" );
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