document.write( "Question 877075: 9m^2-3m-18=0
\n" ); document.write( "please how to solve this equation
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Algebra.Com's Answer #529152 by KMST(5328)\"\" \"About 
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We could begin by dividing both sides of the equal sign by 3.
\n" ); document.write( "It is not absolutely necessary, but it makes calculations a bit easier.
\n" ); document.write( "\"9m%5E2-3m-18=0\"--->\"%289m%5E2-3m-18%29%2F3=0%2F3\"--->\"9m%5E2%2F3-3m%2F3-18%2F3=0\"--->\"3m%5E2-m-6=0\"
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\n" ); document.write( "At this point, if you like the quadratic formula, you can apply it.
\n" ); document.write( "If you do not like formula, you would have to solve it by \"completing the square.\"
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\n" ); document.write( "USING THE QUADRATIC FORMULA:
\n" ); document.write( "If an equation of the type \"ax%5E2%2Bbx%2Bc=0\" has any solution(s),they are given by
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In this case, our variable is \"m\" instead of \"x\", but that does not matter.
\n" ); document.write( "The coefficients of the equation are:
\n" ); document.write( "\"a=3\" , \"b=-1\" , and \"c=-6\" , so
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\n" ); document.write( "The approximate values are \"system%28x=-1.257%2C%22and%22%2Cx=1.591%29\" (rounded to 3 decimal places).
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\n" ); document.write( "COMPLETING THE SQUARE:
\n" ); document.write( "\"3m%5E2-m-6=0\"--->\"m%5E2-%281%2F3%29m-2=0\" (dividing both sides by 3 again
\n" ); document.write( "\"m%5E2-%281%2F3%29m-2=0\"--->\"m%5E2-%281%2F3%29m=2\"
\n" ); document.write( "\"m%5E2-%281%2F3%29m%2B%281%2F6%29%5E2=2%2B%281%2F6%29%5E2\"
\n" ); document.write( "\"%28m-1%2F6%29%5E2=2%2B1%2F36\"
\n" ); document.write( "\"%28m-1%2F6%29%5E2=73%2F36\"
\n" ); document.write( "So --> \"system%28m=1%2F6%2Bsqrt%2873%29%2F6%2C%22or%22%2Cm=1%2F6-sqrt%2873%29%2F6%29\" --> \"m=highlight%28%281+%2B-+sqrt%2873%29%29%2F6%29\"
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