document.write( "Question 877037: The length of a rectangle is twice the width of the rectangle, and it's perimeter is 48cm. Calculate the dimensions of the rectangle, and it's area \n" ); document.write( "
Algebra.Com's Answer #529127 by josgarithmetic(39618)\"\" \"About 
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How length L and width w are related as described:
\n" ); document.write( "\"L=2w\"\r
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\n" ); document.write( "\n" ); document.write( "Using L and w in perimeter 48:
\n" ); document.write( "\"2w%2B2L=48\"
\n" ); document.write( "That can be simplified...
\n" ); document.write( "\"w%2BL=24\"
\n" ); document.write( "And L can be substituted as found from description:
\n" ); document.write( "\"w%2B2w=24\"
\n" ); document.write( "\"3w=24\"
\n" ); document.write( "\"w=24%2F3\"
\n" ); document.write( "\"highlight%28w=8%29\" and \"highlight%28L=16%29\".
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