document.write( "Question 876993: two cars leave the same city at the same time.Both traveling opposite directions. One car is traveling 5 miles faster than the other. After 3 hours both two cars are 393 miles apart. Find the speed of both cars. \n" ); document.write( "
Algebra.Com's Answer #529097 by josmiceli(19441)\"\" \"About 
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You can think of one cart as standing still
\n" ); document.write( "and the other car traveling at the sum
\n" ); document.write( "of their speeds
\n" ); document.write( "-------------------
\n" ); document.write( "Let \"+s+\" = the speed of the slower car in mi/hr
\n" ); document.write( "\"+s+%2B+5+\" = the speed of the faster car in mi/hr
\n" ); document.write( "-------------------
\n" ); document.write( "\"+393+=+%28+s+%2B+s+%2B+5+%29%2A3+\"
\n" ); document.write( "\"+393+=+%28+2s+%2B+5+%29%2A3+\"
\n" ); document.write( "\"+393+=+6s+%2B+15+\"
\n" ); document.write( "\"+6s+=+378+\"
\n" ); document.write( "\"+s+=+63+\"
\n" ); document.write( "\"+s+%2B+5+=+68+\"
\n" ); document.write( "---------------
\n" ); document.write( "Their speeds are 63 mi/hr and 68 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "\"+d%5B1%5D+=+s%2At+\"
\n" ); document.write( "\"+d%5B1%5D+=+63%2A3+\"
\n" ); document.write( "\"+d%5B1%5D+=+189+\"
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+68%2A3+\"
\n" ); document.write( "\"+d%5B2%5D+=+204+\"
\n" ); document.write( "---------------
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+393+\"
\n" ); document.write( "\"+189+%2B+204+=+393+\"
\n" ); document.write( "\"+393+=+393+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" ); document.write( "
\n" );