document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=876933>Question 876933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find the number of sides a polygon has by the measurement of one interior angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529058 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529058\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the polygon is a REGULAR polygon, then the<BR>\n" );
document.write( "measurement of one interior angle (IA) is equal to<BR>\n" );
document.write( "((n-2)*180) / n, where n is the number of sides of the regular polygon, therefore if you know the measure of IA, you can calculate n, that is<BR>\n" );
document.write( "IA = ((n-2)*180) / n<BR>\n" );
document.write( "IA*n = (n-2) * 180<BR>\n" );
document.write( "IA*n = 180n - 360<BR>\n" );
document.write( "IA*n - 180n = -360<BR>\n" );
document.write( "n(IA - 180) = -360<BR>\n" );
document.write( "n = -360 / (IA - 180)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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