document.write( "Question 876872: Solve logx+log(x-3)=log108 \n" ); document.write( "
Algebra.Com's Answer #529045 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! log(x)+log(x-3)=log(108) \n" ); document.write( "log(x*(x-3)) = log(108) \n" ); document.write( "x*(x-3) = 108 \n" ); document.write( "x^2 - 3x = 108 \n" ); document.write( "x^2 - 3x - 108 = 0 \n" ); document.write( "(x - 12)(x + 9) = 0 \n" ); document.write( " x = 12 or x = -9 \n" ); document.write( " |