document.write( "Question 876872: Solve logx+log(x-3)=log108 \n" ); document.write( "
Algebra.Com's Answer #529045 by LinnW(1048)\"\" \"About 
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log(x)+log(x-3)=log(108)
\n" ); document.write( "log(x*(x-3)) = log(108)
\n" ); document.write( "x*(x-3) = 108
\n" ); document.write( "x^2 - 3x = 108
\n" ); document.write( "x^2 - 3x - 108 = 0
\n" ); document.write( "(x - 12)(x + 9) = 0
\n" ); document.write( " x = 12 or x = -9
\n" ); document.write( "
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