document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=876890>Question 876890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three times the measure of an angle is 15 less than the measure of its complement. Find the angle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529039 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> three times the measure of an angle is 15 less than the measure of its complement. Find the angle.<BR>\n" );
document.write( "let angle is X and complementary angle is 90-X<BR>\n" );
document.write( "as per given conditions <BR>\n" );
document.write( "3X+15 =90-X<BR>\n" );
document.write( "3X +x =90-15<BR>\n" );
document.write( "4X= 75<BR>\n" );
document.write( "X=75/4<BR>\n" );
document.write( "X=18.75 degree <BR>\n" );
document.write( "Answer  18.75 degree   or   18 degree and 45 minutes  </SPAN>\n" );
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