document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1521>Question 1521</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Henry planned to move 1/3 of his CD collection in the new cabinet in the morning and the rest in the afternoon. If he moved only 2/3 as many as he planned in the morning, what fraction of his CD's were left to be moved in the afternoon? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #529 by </B><A HREF=/tutors/aboutme.mpl?userid=usyim88hk><B>usyim88hk(158)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=usyim88hk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So lets find out how many CD did he moved<BR>\n" );
document.write( "It will be 1/3 times 2/3 because only 2/3 of the 1/3 are moved<BR>\n" );
document.write( "(1/3)(2/3) = 2/9<BR>\n" );
document.write( "So 2/9 is the total fraction of CD he moved, so there are 1-(2/9) which is also equal to 7/9 of CDs left </SPAN>\n" );
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