document.write( "Question 876684: here is what the question is.\r
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document.write( "Kristen bought her lunch for $6.85. She paid for it with nickels and quarters. If there were 53 quarters, how many of each coin type was there? \n" );
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Algebra.Com's Answer #528985 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 53 quarters = $13.25 ??? \n" ); document.write( "Do you mean she used 53 of them? Or they were just in the vicinity? \n" ); document.write( "=========== \n" ); document.write( "53 nickels = 265 cents. \n" ); document.write( "Each nickel replaced by a quarter add 20 cents \n" ); document.write( "---- \n" ); document.write( "(685 - 265)/20 = 420/21 = 21 quarters \n" ); document.write( "--> 21 quarters & 32 nickels\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |