document.write( "Question 876668: I can't understand how the solution set to (x-4)^(2/3)=16 is {-60,68}? I need precise step-by-step info, because I am looking at an example problem, and I'm still not getting it. \n" ); document.write( "
Algebra.Com's Answer #528943 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Here's an alternate way.  Slightly different:\r\n" );
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document.write( "\"matrix%282%2C1%2C%22%22%2C%0D%0A%0D%0A%0D%0A%28x-4%29%5E%282%2F3%29%29\"\"matrix%282%2C1%2C%22%22%2C%22%22=%22%22%29\"\"matrix%282%2C1%2C%22%22%2C16%29\"\r\n" );
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document.write( "We want to make the exponent \"2%2F3\" become a whole\r\n" );
document.write( "number. So we raise both sides to the 3 power. That is,\r\n" );
document.write( "we cube both sides:\r\n" );
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document.write( "\"%28%28x-4%29%5E%282%2F3%29%29%5E3\"\"%22%22=%22%22\"\"16%5E3\"\r\n" );
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document.write( "\"%28x-4%29%5E2\"\"%22%22=%22%22\"\"4096\"\r\n" );
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document.write( "Use the principle of square roots:\r\n" );
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document.write( "\"x-4\"\"%22%22=%22%22\"\"%22%22+%2B-+sqrt%284096%29\"\r\n" );
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document.write( "\"x-4\"\"%22%22=%22%22\"\"%22%22+%2B-+64\"\r\n" );
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document.write( "x-4 = 64;      x-4 = -64\r\n" );
document.write( "  x = 68;        x = -68\r\n" );
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document.write( "Edwin
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