document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=876668>Question 876668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can't understand how the solution set to (x-4)^(2/3)=16 is {-60,68}? I need precise step-by-step info, because I am looking at an example problem, and I'm still not getting it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #528941 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=528941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-4)^(2/3)=16<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Take the sq root of both sides<BR>\n" );
document.write( "(x-4)^(1/3)= 4<BR>\n" );
document.write( "Cube both sides<BR>\n" );
document.write( "x-4 = 64<BR>\n" );
document.write( "x = 68<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Do the same with sqrt(16) = -4<BR>\n" );
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