document.write( "Question 876577: 5 YEARS AGO A MAN 7 TIMES AS OLD AS HIS SON.AFTER 5 YEARS HE WILL BE THRICE AS OLD AS HIS SON.FIND THEIR PRESENT AGE
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Algebra.Com's Answer #528873 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+f+\" = father's age now
\n" ); document.write( "Let \"+s+\" = son's age now
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\n" ); document.write( "\"+f+-+5+\" = father's age 5 yrs ago
\n" ); document.write( "\"+s+-+5+\" = son's age 5 yrs ago
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\n" ); document.write( "\"+f+%2B+5+\" = father's age in 5 yrs
\n" ); document.write( "\"+s+%2B+5+\" = son's age in 5 yrs
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\n" ); document.write( "(1) \"+f+-+5+=+7%2A%28+s+-+5+%29+\"
\n" ); document.write( "(2) \"+f+%2B+5+=+3%2A%28+s+%2B+5+%29+\"
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\n" ); document.write( "(1) \"+f+-+5+=+7s+-+35+\"
\n" ); document.write( "(1) \"+7s+-+f+=+30+\"
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\n" ); document.write( "(2) \"+f+%2B+5+=+3s+%2B+15+\"
\n" ); document.write( "(2) \"+3s+-+f+=+-10+\"
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\n" ); document.write( "Subtract (2) from (1)
\n" ); document.write( "(1) \"+7s+-+f+=+30+\"
\n" ); document.write( "(2) \"+-3s+%2B+f+=+10+\"
\n" ); document.write( "\"+4s+=+40+\"
\n" ); document.write( "\"+s+=+10\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+f+-+5+=+7%2A%28+s+-+5+%29+\"
\n" ); document.write( "(1) \"+f+-+5+=+7%2A%28+10+-+5+%29+\"
\n" ); document.write( "(1) \"+f+-+5+=+7%2A5+\"
\n" ); document.write( "(1) \"+f+=+40+\"
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\n" ); document.write( "The father is 40 and the son is 10
\n" ); document.write( "This checks out if you read back
\n" ); document.write( "through the problem\r
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