document.write( "Question 876529: The sum of a number of two digits & the number obtained on inter–
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document.write( "changing the digits is 99. If 5 is added to the number , then it is 4 less
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document.write( "than 6 times the sum of the digits. Find the number \n" );
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Algebra.Com's Answer #528838 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Let the number be xy\r \n" ); document.write( "\n" ); document.write( "10x+y+10y+x=99\r \n" ); document.write( "\n" ); document.write( "11x+11y=99 \n" ); document.write( "/11 \n" ); document.write( "x+y=9.....................(1)\r \n" ); document.write( "\n" ); document.write( "ii condition\r \n" ); document.write( "\n" ); document.write( "10x+y+5 = 6(x+y)-4\r \n" ); document.write( "\n" ); document.write( "10x+y+5=6x+6y-4\r \n" ); document.write( "\n" ); document.write( "4x-5y=-9..................(2)\r \n" ); document.write( "\n" ); document.write( "solve (1) &(2)\r \n" ); document.write( "\n" ); document.write( "1 x + 1 y = 9 .............1 \n" ); document.write( " \n" ); document.write( "4 x -5 y = -9 .............2 \n" ); document.write( "-5 y \n" ); document.write( "multiply (1)by 5 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "5 x 5 y = 45 \n" ); document.write( "4 x -5 y = -9 \n" ); document.write( "Add the two equations \n" ); document.write( "9 x = 36 \n" ); document.write( "/ 9 \n" ); document.write( "x = 4 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1 x + 1 y = 9 \n" ); document.write( "4 + y = 9 \n" ); document.write( " y = 9 -4 \n" ); document.write( " y = 5 \n" ); document.write( " y = 5 \n" ); document.write( "the number is 45 \n" ); document.write( " |