document.write( "Question 876532: need help graphing the equation y=10x-2 \n" ); document.write( "
Algebra.Com's Answer #528824 by jim_thompson5910(35256)\"\" \"About 
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Looking at \"y=10x-2\" we can see that the equation is in slope-intercept form \"y=mx%2Bb\" where the slope is \"m=10\" and the y-intercept is \"b=-2\" \r
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\n" ); document.write( "\n" ); document.write( "Since \"b=-2\" this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis\r
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\n" ); document.write( "\n" ); document.write( "Now since the slope is comprised of the \"rise\" over the \"run\" this means\r
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\n" ); document.write( "\n" ); document.write( "Also, because the slope is \"10\", this means:\r
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\n" ); document.write( "\n" ); document.write( "\"rise%2Frun=10%2F1\"\r
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\n" ); document.write( "\n" ); document.write( "which shows us that the rise is 10 and the run is 1. This means that to go from point to point, we can go up 10 and over 1\r
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\n" ); document.write( "\n" ); document.write( "So starting at , go up 10 units \r
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\n" ); document.write( "\n" ); document.write( "and to the right 1 unit to get to the next point \r
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\n" ); document.write( "\n" ); document.write( "Now draw a line through these points to graph \"y=10x-2\"\r
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\n" ); document.write( "\n" ); document.write( " So this is the graph of \"y=10x-2\" through the points and
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