document.write( "Question 876274: a man covers a distance of 24 km in 3.5 hours partly on foot at speed of 4.5 km per hour and partly on bicycle at speed of 10 km per hour.Find the distance covered on foot. \n" ); document.write( "
Algebra.Com's Answer #528803 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a man covers a distance of 24 km in 3.5 hours partly on foot at speed of 4.5 km per hour and partly on bicycle at speed of 10 km per hour. \n" ); document.write( "Find the distance covered on foot. \n" ); document.write( ": \n" ); document.write( "Let w = his distance on foot \n" ); document.write( "the total distance is given as 24 km, therefore \n" ); document.write( "(24-w) = dist by bicycle \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( ": \n" ); document.write( "Walk time + bike time = 3.5 hrs \n" ); document.write( " \n" ); document.write( "multiply by 90 to clear the denominators \n" ); document.write( "20w + 9(24-w) = 90(3.5) \n" ); document.write( "20w + 216 - 9w = 315 \n" ); document.write( "20w - 9w = 315 - 216 \n" ); document.write( "11w = 99 \n" ); document.write( "w = 99'/11 \n" ); document.write( "w = 9 mi on foot \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this, find the actual time walking and riding (ride dist 24-9) \n" ); document.write( "9/4.5 = 2 hrs \n" ); document.write( "15/10 = 1.5 hrs \n" ); document.write( "-------------- \n" ); document.write( "total: 3.5 hrs \n" ); document.write( " |