document.write( "Question 876487: A plane travels 300 miles against the wind in five hours, then turns and travels 330 miles with the wind in three hours.Find the speed of the wind and the speed of the plane . \n" ); document.write( "
Algebra.Com's Answer #528792 by mananth(16946)\"\" \"About 
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Plane speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 5 hours
\n" ); document.write( "with wind 3 hours
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\n" ); document.write( "Distance against 300 miles distance with 330 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "300.00 / ( x - y )= 5.00
\n" ); document.write( "5.00 ( x - y ) = 3.00
\n" ); document.write( "5.00 x - 5.00 y = 300.00 ....................1
\n" ); document.write( "
\n" ); document.write( "330.00 / ( x + y )= 3.00
\n" ); document.write( "3.00 ( x + y ) = 330.00
\n" ); document.write( "3.00 x + 3.00 y = 330.00 ...............2
\n" ); document.write( "Multiply (1) by 3.00
\n" ); document.write( "Multiply (2) by 5.00
\n" ); document.write( "we get
\n" ); document.write( "15.00 x + -15.00 y = 900.00
\n" ); document.write( "15.00 x + 15.00 y = 1650.00
\n" ); document.write( "30.00 x = 2550.00
\n" ); document.write( "/ 30.00
\n" ); document.write( "x = 85.00 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "5.00 x -5.00 y = 300.00
\n" ); document.write( "425.00 -5.00 -425.00 = 300.00
\n" ); document.write( "-5.00 y = 300.00
\n" ); document.write( "-5.00 y = -125.00 mph
\n" ); document.write( " y = 25.00
\n" ); document.write( "Plane speed 85.00 mph
\n" ); document.write( "wind speed 25.00 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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