document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73894>Question 73894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 4 less than 3 times another. If the sum of the numbers is 36, what are the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52876 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52876\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=36<BR>\n" );
document.write( "X=36-Y<BR>\n" );
document.write( "X=3Y-4 THUS WE SUBSTITUTE (3Y-4) FOR X IN THE OTHER EQUATION & WE GET.<BR>\n" );
document.write( "(3Y-4)=36-Y<BR>\n" );
document.write( "3Y-4=36-Y<BR>\n" );
document.write( "3Y+Y=36+4<BR>\n" );
document.write( "4Y=40<BR>\n" );
document.write( "Y=10 ANSWER NOW SUBSTITUTE 10 FOR Y & SOLVE FOR X<BR>\n" );
document.write( "X+10=36<BR>\n" );
document.write( "X=36-10<BR>\n" );
document.write( "X=26 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "26=3*10-4<BR>\n" );
document.write( "26=30-4<BR>\n" );
document.write( "26=26 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );