document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=876340>Question 876340</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the Area of a right triangle is 24x^3+8x^2-12x-4. which of the following could be the base and the height ?\r<BR>\n" );
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document.write( "a)(4x^2+1)(3x-2)\r<BR>\n" );
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document.write( "b)(4x^2-2)(3x+2)\r<BR>\n" );
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document.write( "C) (4x^2+2)(3x-1)\r<BR>\n" );
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document.write( "D) (4x^2-2) (3x-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #528744 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=528744\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> None of them.<BR>\n" );
document.write( "Use FOIL to multiply <BR>\n" );
document.write( "1/2 b*h=24x^3+8x^2-12x-4<BR>\n" );
document.write( "a) (4x^2+1)(3x-2)=12x^3-8x^2+3x-2<BR>\n" );
document.write( "b) (4x^2-2)(3x+2)=12x^3+8x^2-6x-4<BR>\n" );
document.write( "C) (4x^2+2)(3x-1)=12x^3-4x^2+6x-2<BR>\n" );
document.write( "D) (4x^2-2)(3x-1)=12x^3-4x^2-6x+2<BR>\n" );
document.write( "We want half of those amounts not double.<BR>\n" );
document.write( "Only b has the right signs.<BR>\n" );
document.write( "Which one works out to 24x^3+8x^2-12x-4\r<BR>\n" );
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document.write( "Remember you take 1/2 of b*h\r<BR>\n" );
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document.write( " </SPAN>\n" );
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