document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=876358>Question 876358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the center and radius of the circle with the given equation.\r<BR>\n" );
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document.write( "(x + 4)2 + (y - 1)2 = 25\r<BR>\n" );
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document.write( " a<BR>\n" );
document.write( "center (-4, 1); radius = 25<BR>\n" );
document.write( " b<BR>\n" );
document.write( "center (4, -1); radius = 5<BR>\n" );
document.write( " c<BR>\n" );
document.write( "center (-4, 1); radius = 5<BR>\n" );
document.write( " d<BR>\n" );
document.write( "center (4, -1); radius = 25<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #528726 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=528726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Standard Form of an Equation of a Circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 ALIGN=MIDDLE  ALT=\"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "where Pt(h,k) is the center and r is the radius<BR>\n" );
document.write( "(x + 4)^2 + (y - 1)^2 = 25  C(-4,1) , r = 5 </SPAN>\n" );
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