document.write( "Question 876257: Please help me answer this question. I need the answer as soon as possible. Question: Find an equation of the line containing(3,-2) and tangent to 4x^2+y^2=8. Not using the principle of derivatives. Thank you.
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Algebra.Com's Answer #528667 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
This is an ellipse with its major axis on the y axis and whose center is the origin (0,0), the point of tangent to this ellipse is the point of the negative major axis.
\n" ); document.write( "4x^2 + y^2 = 8
\n" ); document.write( "divide both sides of the = by 8
\n" ); document.write( "x^2/2 + y^2/8 = 1
\n" ); document.write( "the major axis is + or - square root of 8 = + or - 2.82
\n" ); document.write( "so the point is (0, -2.8) the other point is (3, -2)
\n" ); document.write( "standard form of line is y = mx + b, where m is slope and b is y intercept
\n" ); document.write( "m = (-2.8 - (-2)) / 0 - 3) = -0.8 / -3 = 0.27
\n" ); document.write( "y = 0.27x + b
\n" ); document.write( "b = y - 0.27x
\n" ); document.write( "b = -2 - 0.27(3)
\n" ); document.write( "b = -2.81 and equation of the tanget line is
\n" ); document.write( "y = 0.27x - 2.81
\n" ); document.write( "note that the difference between the negative major axis point (0, -2.82) and the y intercept is the rounding of the slope value
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