document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=876192>Question 876192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An engineer thinks that the best model for time between breakdowns<BR>\n" );
document.write( "of a generator is the exponential distribution with a mean of 15 days.<BR>\n" );
document.write( "(a) If the generator has just broken down, what is the probability that it<BR>\n" );
document.write( "will break down in the next 21 days?<BR>\n" );
document.write( "(b) What is the probability that the generator will operate for 30 days<BR>\n" );
document.write( "without a breakdown?<BR>\n" );
document.write( "(c) If the generator has been operating for the last 20 days, what is the<BR>\n" );
document.write( "probability that it will operate for another 30 days without a<BR>\n" );
document.write( "breakdown?<BR>\n" );
document.write( "(d) Comment on the results of parts (b) and (c). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #528641 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=528641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Average Time <u>between breakdowns</u> of a generator = 15days<BR>\n" );
document.write( "a) P = poissonpdf(15,21)= .02986<BR>\n" );
document.write( "b) P = poissonpdf(15,30)= .0002<BR>\n" );
document.write( "c. P = poissonpdf(15,50)= 6.4x10^(-13)<BR>\n" );
document.write( "d) Better Chance of operating 30days, after a breakdown than w/0 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );