document.write( "Question 876190: How do i establish the identity\r
\n" ); document.write( "\n" ); document.write( "sin^3 theta - cos^3 theta/sin theta - cos theta = 1 + sin theta cos theta
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Algebra.Com's Answer #528629 by dkppathak(439)\"\" \"About 
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How do i establish the identity
\n" ); document.write( "sin^3 theta - cos^3 theta/sin theta - cos theta = 1 + sin theta cos theta
\n" ); document.write( "we know a^3-b^3= (a-b)(a^2 + ab +b^2)
\n" ); document.write( "using formula
\n" ); document.write( "sin^3theta -cos^3theta = (sin theta -cos theta )(sin^2theta +cos^2 theta +sin theta. cos theta )
\n" ); document.write( "(sin^3 theta - cos^3 theta)/(sin theta - cos theta)
\n" ); document.write( "=(sin theta -cos theta )(sin^2theta +cos^2 theta +sin theta. cos theta )/sin theta - cos theta)
\n" ); document.write( "=(sin^2 theta + cos^2 theta + sin theta cos theta )
\n" ); document.write( "we know sin^2 theta + cos^2 theta =1 by substituting the value
\n" ); document.write( "=
\n" ); document.write( "=(sin^2 theta + cos^2 theta + sin theta cos theta ) = (1+ sin theta cos theta )
\n" ); document.write( "answer
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