document.write( "Question 876166: You have quarters and dimes, totaling $3.10, 22 coins in all. How many of each coin do you have?
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document.write( "I need to figure it out algebraically using substitution or elimination. \r
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document.write( "I thought the following would work but I can't get it right... please help!!
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document.write( ".25q+.10d=3.10
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document.write( "I feel like 22 should be involved in the equation but I'm not sure where.\r
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document.write( "Thank you in advance for any help you can give me!\r
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Algebra.Com's Answer #528600 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! You have one equation, but you need 2 (2 equations needed to solve for 2 variables)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your other equation will be d + q = 22 (# of dimes + # of quarters = total) because you have 22 coins total. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve d + q = 22 for q to get q = 22 - d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then plug that into the first equation to get 0.25(22 - d) + 0.10d = 3.10 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll let you finish up from here. \n" ); document.write( " |