document.write( "Question 876149: James covers a distance of 8 meters in the first second of a 100 meter race. Then he sprints at a speed of 9 meters per second. How far is James from the finish line 9 seconds after the race has started? My teacher gave me the equation
\n" ); document.write( "an=a1+(n-1)d i just dont understand what to plug in.
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Algebra.Com's Answer #528596 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Here's how I would do it:
\n" ); document.write( "\"+d+=+r%2At+\"
\n" ); document.write( "9 sec after the race started is 8 sec after
\n" ); document.write( "he started sprinting
\n" ); document.write( "\"+d+=+9%2A8+\"
\n" ); document.write( "\"+d+=+72+\"
\n" ); document.write( "So, he has gone \"+8+%2B+72+=+80+\" m
\n" ); document.write( "That means he is \"+100+-+80+=+20+\" m
\n" ); document.write( "from the finish line
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\n" ); document.write( "Putting into a formula:
\n" ); document.write( "Let \"+d+\" = distance from the finish line
\n" ); document.write( "after 9 sec
\n" ); document.write( "\"+d+=+100+-+%28+9%2A%28+9-1+%29+%29+-+8+\"
\n" ); document.write( "\"+d+=+100+-+72+-+8+\"
\n" ); document.write( "\"+d+=+20+\" m
\n" ); document.write( "where \"+%28+9%2A%28+9-1+%29+%29+\" = rate x time\r
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