document.write( "Question 876120: plz help me solve this \r
\n" ); document.write( "\n" ); document.write( "tan-1[tan(200)] where 200 is in radians. \r
\n" ); document.write( "\n" ); document.write( "I've tied to solve it:
\n" ); document.write( "x must be -pi/2 < x < pi/2 \r
\n" ); document.write( "\n" ); document.write( "x= 200rad - pi = 20 rad (since tan is periodic)\r
\n" ); document.write( "\n" ); document.write( "so tan(inverse)(tan 20rad)= 20rad
\n" ); document.write( "because tan invrse and tan cancel each other
\n" ); document.write( "is my answer correct?? \n" ); document.write( "
Algebra.Com's Answer #528581 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
tan (inverse)(tan 200 rad)\r
\n" ); document.write( "\n" ); document.write( "I've tied to solve it:
\n" ); document.write( "x must be -pi/2 < x < pi/2 \r
\n" ); document.write( "\n" ); document.write( "x= 200rad - pi = 20 rad (since tan is periodic)\r
\n" ); document.write( "\n" ); document.write( "so tan(inverse)(tan 20rad)= 20rad
\n" ); document.write( "because tan invrse and tan cancel each other
\n" ); document.write( "is my answer correct??
\n" ); document.write( "============
\n" ); document.write( "tan (inverse)(tan 200 rad) = 200 rad
\n" ); document.write( "----
\n" ); document.write( "Subtract 2pi repeatedly until it's <= 2pi
\n" ); document.write( "= (200 MOD (2pi))*(2pi) =~ 5.221 radians
\n" ); document.write( "5.221 is not between -pi/2 and pi/2, so
\n" ); document.write( "5.221 - 2pi = -1.0619 radians
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\n" ); document.write( "email via the TY note if you don't know modulus aritmetic.
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