document.write( "Question 73872: ) For a fixed rate, a fixed principal amount, and a fixed compounding cycle, the return is an exponential function of time. Using the formula, A=P(1+r/n)^nt , let r = 10%, P = 1, and n = 1 and give the coordinates (t, A) for the points where t = 0, 1, 2, 3, 4. Round your answer to the hundredth's place.\r
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\n" ); document.write( "\n" ); document.write( "b) Show graph here
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Algebra.Com's Answer #52858 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
When you make the substitutions of values given in the problem, the equation becomes:
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\n" ); document.write( "\"A+=+1%2A%281%2B%280.1%2F1%29%29%5E%281%2At%29\"
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\n" ); document.write( "When you do the math this further reduces to:
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\n" ); document.write( "\"A+=+%281.1%29%5Et\"
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\n" ); document.write( "Now all you have to do is to substitute (one at a time) for t the following values:
\n" ); document.write( "0, 1, 2, 3, 4.
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\n" ); document.write( "The first substitution is easy because any number raised to the 0 power is 1. So
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\n" ); document.write( "\"A+=+%281.1%29%5E0+=+1\"
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\n" ); document.write( "And the next substitution is just as easy because any number raised to the 1 power is
\n" ); document.write( "just itself.
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\n" ); document.write( "\"A+=+%281.1%29%5E1+=+1.1\"
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\n" ); document.write( "The next one is not too bad because \"%281.1%29%5E2+=+1.21\"
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\n" ); document.write( "The rest is quick work on a calculator to get \"%281.1%29%5E3+=+1.33\" and \"%281.1%29%5E4+=+1.46\"
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\n" ); document.write( "So the points to plot are:
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\n" ); document.write( "(0,1) (1,1.1) (2,1.21) (3,1.33) and (4,1.46)
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\n" ); document.write( "When you plot these points the graph should look like:
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\n" ); document.write( "\"graph%28300%2C300%2C0%2C4%2C0%2C2%2C%281.1%29%5E%28x%29%29\"
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\n" ); document.write( "Note that the graph is NOT a straight line. It is the beginning of an exponential
\n" ); document.write( "curve whose rise gets much steeper as t gets larger and larger.
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\n" ); document.write( "You now have the points, the work, and a view of the graph. That should help you with the
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