document.write( "Question 876037: An arrow is shot into the air is 144t - 4.9t2 meters above the ground t seconds after it is released. During what period(s) of time is the arrow above 68.6 meters? Round your answer to the nearest .01 second.
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Algebra.Com's Answer #528532 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
t = .48sec and
\n" ); document.write( "68.6 = -4.9t^2 + 144t
\n" ); document.write( " -4.9t^2 + 144t - 68.6 = 0
\n" ); document.write( "t = .48 and t = 28.90
\n" ); document.write( "from t = .48sec to 28.90sec
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-4.9x%5E2%2B144x%2B-68.6+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28144%29%5E2-4%2A-4.9%2A-68.6=19391.44\".
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\n" ); document.write( " Discriminant d=19391.44 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-144%2B-sqrt%28+19391.44+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28144%29%2Bsqrt%28+19391.44+%29%29%2F2%5C-4.9+=+0.484372370178204\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28144%29-sqrt%28+19391.44+%29%29%2F2%5C-4.9+=+28.9033827318626\"
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\n" ); document.write( " Quadratic expression \"-4.9x%5E2%2B144x%2B-68.6\" can be factored:
\n" ); document.write( " \"-4.9x%5E2%2B144x%2B-68.6+=+-4.9%28x-0.484372370178204%29%2A%28x-28.9033827318626%29\"
\n" ); document.write( " Again, the answer is: 0.484372370178204, 28.9033827318626.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-4.9%2Ax%5E2%2B144%2Ax%2B-68.6+%29\"
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