document.write( "Question 876025: Determine the coordinates of the focus of the parabola y= 1/16 x2
\n" ); document.write( "Be sure to write your answer as an ordered pair.
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Algebra.Com's Answer #528520 by ewatrrr(24785) $\"\"$ $\"About$

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y= (1/16) x^2 Opens Upward along x = 0
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\n" ); document.write( "1/16 = 1/(4p) = 1/16, p = 4
\n" ); document.write( "F(0,4)
\n" ); document.write( "the vertex form of a Parabola opening up(a>0) or down(a<0), $\"y=a%28x-h%29%5E2+%2Bk\"$
\n" ); document.write( "where(h,k) is the vertex and x = h is the Line of Symmetry
\n" ); document.write( "The standard form is $\"%28x+-h%29%5E2+=+4p%28y+-k%29\"$ , 0r a = 1/4p, where the focus is (h,k + p)
\n" ); document.write( "With Directrix y = (k - p)
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