document.write( "Question 73721: (2xy+3wxy-8x-12wx)/(4xy^2-64x) \n" ); document.write( "

Algebra.Com's Answer #52852 by rmromero(383) $\"\"$ $\"About$

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document.write( "                2xy + 3wxy - 8x - 12wx 
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document.write( "                     4xy^2 - 64x\r
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document.write( "Factor the numerator and denominator\r
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document.write( "               (2xy - 8x) + (3wxy - 12wx) 
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document.write( "                     4x(y^2 - 16)\r
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document.write( "                 2x(y - 4) + 3wx(y - 4) 
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document.write( "                    4x(y - 4)(y + 4)\r
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document.write( "                 (2x + 3wx)(y - 4) 
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document.write( "                    4x(y - 4)(y + 4)\r
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document.write( "                    x(2 + 3w)(y - 4) 
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document.write( "                    4x(y - 4)(y + 4)\r
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document.write( "                    
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document.write( "                 2 + 3w
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document.write( "                4(y + 4)
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