document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73871>Question 73871</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 40% alcohol solution must be mixed with 70 gallons of a 21% slution to obtain a solution that is 30% alcohol </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52848 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52848\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 40% alcohol solution must be mixed with 70 gallons of a 21% solution to obtain a solution that is 30% alcohol.<BR>\n" );
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document.write( "21% solution DATA:<BR>\n" );
document.write( "Amt = 70 gals ; amt of alcohol = 0.21*70 = 14.7 gals<BR>\n" );
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document.write( "40% solution DATA:<BR>\n" );
document.write( "Amt = x gals ; amt of alcohol = 0.40x gals<BR>\n" );
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document.write( "30% solution DATA:<BR>\n" );
document.write( "Amt = 70+x gals ; amt of alcohol = 0.3(70+x) = 21 + 0.3x gals<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "alcohol + alcohol = alcohol<BR>\n" );
document.write( "14.7 + 0.4x = 21 + 0.3x<BR>\n" );
document.write( "0.1x = 6.3 <BR>\n" );
document.write( "x=63 gallons (amt of 40% solution that must be added)<BR>\n" );
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document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );