document.write( "Question 875750: In triangle ABC, angle A is twice the sum of angles B and C. Angle B is 24 degrees. What is the measure of Angle A?\r
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Algebra.Com's Answer #528411 by jim_thompson5910(35256)\"\" \"About 
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\"angle A is twice the sum of angles B and C\" so A = 2*(B+C)\r
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\n" ); document.write( "\n" ); document.write( "Since B = 24, we know\r
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\n" ); document.write( "\n" ); document.write( "A = 2*(B+C)\r
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\n" ); document.write( "\n" ); document.write( "A = 2*(24+C)\r
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\n" ); document.write( "\n" ); document.write( "A = 2*24+2C\r
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\n" ); document.write( "\n" ); document.write( "A = 48 + 2C\r
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\n" ); document.write( "\n" ); document.write( "All 3 angles add to 180 degrees, so A+B+C = 180\r
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\n" ); document.write( "\n" ); document.write( "A+B+C = 180\r
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\n" ); document.write( "\n" ); document.write( "A+24+C = 180 ... plug in B = 24\r
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\n" ); document.write( "\n" ); document.write( "48+2C+24+C = 180 ... plug in A = 48+2C, now solve for C\r
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\n" ); document.write( "\n" ); document.write( "48+2C+24+C = 180\r
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\n" ); document.write( "\n" ); document.write( "72+3C = 180\r
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\n" ); document.write( "\n" ); document.write( "3C = 180-72\r
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\n" ); document.write( "\n" ); document.write( "3C = 108\r
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\n" ); document.write( "\n" ); document.write( "C = 108/3\r
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\n" ); document.write( "\n" ); document.write( "C = 36\r
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\n" ); document.write( "\n" ); document.write( "Use this to find A\r
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\n" ); document.write( "\n" ); document.write( "A = 48+2C\r
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\n" ); document.write( "\n" ); document.write( "A = 48+2*36 ... plug in C = 36\r
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\n" ); document.write( "\n" ); document.write( "A = 48+72\r
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\n" ); document.write( "\n" ); document.write( "A = 120
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