document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=875684>Question 875684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose the obtained z was -2.5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #528372 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=528372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Re TY: .0062 < .05 (popular 5% confidence Interval) reject.<BR>\n" );
document.write( "z = -2.5, P(z < -2.5) = .0062  0r .62% of the Area under the normal curve is left of z = -2.5<BR>\n" );
document.write( "Below:  z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.  <BR>\n" );
document.write( "Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and %50 to the right<BR>\n" );
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