document.write( "Question 875547: Im stuck, please help me solve and go into detail
\n" ); document.write( "Find the exact value
\n" ); document.write( "Given that sin Ө = -4/5 with Ө in quadrant IV, find tan 2Ө
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Algebra.Com's Answer #528345 by lwsshak3(11628)\"\" \"About 
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Find the exact value
\n" ); document.write( "Given that sin Ө = -4/5 with Ө in quadrant IV, find tan 2Ө
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\n" ); document.write( "you are working with a (3-4-5) reference right triangle in quadrant IV
\n" ); document.write( "sin Ө=-4/5 (given)
\n" ); document.write( "cos Ө=3/5
\n" ); document.write( "sin 2Ө=2sinӨcosӨ=2*-4/5*3/5=-24/25
\n" ); document.write( "cos 2Ө=cos^2Ө-sin^2Ө=9/25-16/25=-7/25
\n" ); document.write( "tan 2Ө-sin 2Ө/cos 2Ө=24/7
\n" ); document.write( "..
\n" ); document.write( "Check:
\n" ); document.write( "sin Ө=-4/5
\n" ); document.write( "Ө≈306.87˚
\n" ); document.write( "2Ө≈613.74˚
\n" ); document.write( "tan 2Ө≈3.4286…
\n" ); document.write( "exact value as calculated=24/7≈3.4287…
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