document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=875610>Question 875610</A>: <I><SPAN STYLE=\"word-break: break-all;\">  how do I solve 8 + log12(m-10) = 10  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #528313 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=528313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8 + log12(m-10) = 10<BR>\n" );
document.write( "subtract 8 from both sides of =<BR>\n" );
document.write( "log12(m-10) = 2<BR>\n" );
document.write( "by definition of logarithm<BR>\n" );
document.write( "m-10 = 12^2<BR>\n" );
document.write( "m-10 = 144<BR>\n" );
document.write( "m = 154\r<BR>\n" );
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