document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=875557>Question 875557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help I have the equation:<BR>\n" );
document.write( "(1/8)*2^(-3r) = 2^(-r)<BR>\n" );
document.write( "I need to solve for r but i do do not know how since I have that \"1/8\" please help me understand why we do each step to solve the problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #528281 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=528281\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F8%292%5E%28-3r%29+=+2%5E%28-r%29 ALIGN=MIDDLE  ALT=\"%281%2F8%292%5E%28-3r%29+=+2%5E%28-r%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%5E%28-3%29%292%5E%28-3r%29+=+2%5E%28-r%29 ALIGN=MIDDLE  ALT=\"%282%5E%28-3%29%292%5E%28-3r%29+=+2%5E%28-r%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2%5E%28-3r+-+3%29+=+2%5E%28-r%29 ALIGN=MIDDLE  ALT=\"+2%5E%28-3r+-+3%29+=+2%5E%28-r%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "      -3r-3 = -r<BR>\n" );
document.write( "         -3 = 2r<BR>\n" );
document.write( "         -3/2 = r </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );