document.write( "Question 73856: Not sure if this is the right page for this. Can someone help me solve this problem. I'm trying to make head and tails out of it.\r
\n" ); document.write( "\n" ); document.write( "5 < 2(a+1)-3(1-a)\r
\n" ); document.write( "\n" ); document.write( "What i'm getting is 5 < -1a-1 not sure if right solution
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Algebra.Com's Answer #52824 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "5 < 2(a+1)-3(1-a)
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\n" ); document.write( "You can operate on this just as you would an equation, with a major exception that I'll discuss
\n" ); document.write( "later. The goal is to solve for \"a\" in the inequality just as you would solve for \"a\" if
\n" ); document.write( "this were and equation ... having an = sign in place of the < sign.
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\n" ); document.write( "Begin by doing the two distributed multiplications on the right side to get:
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\n" ); document.write( "5 < 2a + 2 - 3 + 3a
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\n" ); document.write( "Combine like terms on the right side. The 2a and the 3a add to 5a and the +2 and -3 add to -1.
\n" ); document.write( "Substitute these values into the inequality and you get:
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\n" ); document.write( "5 < 5a -1
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\n" ); document.write( "Now we need to get rid of the -1 on the right side. Do this by adding +1 to both sides of
\n" ); document.write( "the inequality:
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\n" ); document.write( "5 +1 < 5a -1 +1
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\n" ); document.write( "On the left side add the 5 and +1 to get 6 and on the right side the -1 and +1 cancel each
\n" ); document.write( "other out. Therefore, the inequality now becomes:
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\n" ); document.write( "6 < 5a
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\n" ); document.write( "Finally, solve for \"a\" by dividing both sides by 5. This gives you:
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\n" ); document.write( "6/5 < a
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\n" ); document.write( "Read this as \"a\" must be bigger than 6/5. You can also write the answer as:
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\n" ); document.write( "a > 6/5
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\n" ); document.write( "The \"arrow\" points to the smaller term.
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\n" ); document.write( "Let's check by letting a = 1. That is less than 6/5 so the original inequality should not
\n" ); document.write( "work for the value a = 1. Try it:
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\n" ); document.write( "5 < 2(a+1)-3(1-a) and when a = 1 this becomes
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\n" ); document.write( "5 < 2(1+1) - 3(1-1)
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\n" ); document.write( "5 < 2(2) - 3(0)
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\n" ); document.write( "5 < 4 ... just as you should expect. This does not work because a was less than 6/5 not
\n" ); document.write( "greater than.
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\n" ); document.write( "Let's do a similar check by letting x = 2. That is greater than 6/5 so it shoul make the
\n" ); document.write( "inequality work.
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\n" ); document.write( "5 < 2(a+1)-3(1-a) and let a = 2
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\n" ); document.write( "5 < 2(2+1) - 3(1 - 2)
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\n" ); document.write( "5 < 2(3) - 3(-1)
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\n" ); document.write( "5 < 6 + 1
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\n" ); document.write( "5 < 7
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\n" ); document.write( "5 is less than 7, so this time our check worked, as it was supposed to do because we
\n" ); document.write( "used a value of a greater than 6/5. Our answer is good.
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\n" ); document.write( "Previously I mentioned that you could work inequalities just as you would an equation. There
\n" ); document.write( "is an exception, however. That exception is that whenever you multiply or divide both
\n" ); document.write( "sides of an inequality by a negative number, you must reverse the direction of the inequality.
\n" ); document.write( "We did not have to make use of this rule in this particular problem.
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\n" ); document.write( "Hope this helps you to understand inequalities a little better.
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