document.write( "Question 875405: In a recent poll 73% of 3011 adult surveyed said they use the Internet. construct a 98% confidence interval for the proportion of all adults use the Internet \n" ); document.write( "

Algebra.Com's Answer #528223 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "ME(In %) = z*sqrt(pq/n) = = .019 0r  2%
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document.write( "CI: 73%-ME < u <  73% + ME \n" );
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