document.write( "Question 875481: A square and a rectangle have the same width. The length of the rectangle is 5 times the width. If the sum of the two perimeters is 112 cm, find the length of the rectangle \n" ); document.write( "
Algebra.Com's Answer #528205 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the perimeter of the square is equal to 4w. \n" ); document.write( "the perimeter of the rectangle is equal to 2l + 2w \n" ); document.write( "l is equal to 5w. \n" ); document.write( "the perimeter of the rectangle is equal to 2*5w + 2w \n" ); document.write( "the perimeter of the rectangle is equal to 12w \n" ); document.write( "the sum of the perimeter is equal to 4w + 12 w = 16w \n" ); document.write( "the sum of the perimeters is equal to 112 cm. \n" ); document.write( "w is equal to 112 / 16 = 7 \n" ); document.write( "l is equal to 5 * 7 = 35 \n" ); document.write( "perimeter of square is equal to 4*7 = 28 \n" ); document.write( "perimeter of rectangle id equal to 2*35 + 2*7 = 70 + 14 = 84. \n" ); document.write( "sum of the perimeters is equal to 28 + 84 = 112.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |