document.write( "Question 875444: Mark is 12 years older than Denise. In 6 years time Mark will be twice as old as Denise. What are their ages now? \n" ); document.write( "

Algebra.Com's Answer #528197 by mareebsiddiqui(7) $\"\"$ $\"About$

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Denise's age = x
\n" ); document.write( "Mark's age = x + 12\r
\n" ); document.write( "\n" ); document.write( "After 6 Years:
\n" ); document.write( "Denise's age = 6 + x
\n" ); document.write( "Mark's age = 2(6 + x) = 12 + 2x\r
\n" ); document.write( "\n" ); document.write( "So:
\n" ); document.write( "Before 6 year's Mark's age - Before 6 year's Denise's age = New Mark's age + New Denise's age
\n" ); document.write( "Difference of ages before 6 years = Difference of ages after 6 years
\n" ); document.write( "(x + 12) - x = (12 + 2x) - (6 + x)
\n" ); document.write( "12 = x - 6
\n" ); document.write( "x = 12 - 6 = 6\r
\n" ); document.write( "\n" ); document.write( "New ages of both are:
\n" ); document.write( "Denise's age = 6 + 6 = 12
\n" ); document.write( "Mark's age = 12 + 2x = 12 + 2(6) = 12 + 12 = 24\r
\n" ); document.write( "\n" ); document.write( "Verification of answer:
\n" ); document.write( "Now Mark's age is 12 years older and twice as Denise's age. \n" ); document.write( "

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