document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=875435>Question 875435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 24. Adding five times the smaller number to the greater number gives 68. Find the numbers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #528166 by </B><A HREF=/tutors/aboutme.mpl?userid=bond><B>bond(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bond><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=528166\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let G be the Greater Number and S be the Smaller Number.\r<BR>\n" );
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document.write( "G + S = 24 ............(1)<BR>\n" );
document.write( "G + 5S = 68 ............(2)\r<BR>\n" );
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document.write( "Eq. (2) - (1) yields\r<BR>\n" );
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document.write( "4S = 68 -24;<BR>\n" );
document.write( "S = 11;\r<BR>\n" );
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document.write( "Hence putting S = 11 in eq. (1) or (2) yields G = 13.\r<BR>\n" );
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