document.write( "Question 875328: The perimeter of a rectangle is 190. The length is 9 more than the width.
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document.write( "What is the length of the rectangle?
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document.write( "A) 80 B) 43 C) 52 D)58 E)180 \n" );
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Algebra.Com's Answer #528141 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let x be the width, then the length is x+9, therefore \n" ); document.write( "2x + 2(x+9) = 190 \n" ); document.write( "x + (x+9) = 95 \n" ); document.write( "2x = 86 \n" ); document.write( "x = 43 \n" ); document.write( "Length of rectangle is 43+9 = 52, therefore the answer is C\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |