document.write( "Question 875328: The perimeter of a rectangle is 190. The length is 9 more than the width.
\n" ); document.write( "What is the length of the rectangle?
\n" ); document.write( "A) 80 B) 43 C) 52 D)58 E)180
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Algebra.Com's Answer #528141 by rothauserc(4718)\"\" \"About 
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let x be the width, then the length is x+9, therefore
\n" ); document.write( "2x + 2(x+9) = 190
\n" ); document.write( "x + (x+9) = 95
\n" ); document.write( "2x = 86
\n" ); document.write( "x = 43
\n" ); document.write( "Length of rectangle is 43+9 = 52, therefore the answer is C\r
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