document.write( "Question 875359: A square with an area of 144 square centimeters was increased in length, but not width, until the resulting rectangle had a perimeter that was 4 times the perimeter of the original square. By how many square centimeters did the area of the figure increase? \n" ); document.write( "
Algebra.Com's Answer #528129 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A square with an area of 144 square centimeters was increased in length, but not width, until the resulting rectangle had a perimeter that was 4 times the perimeter of the original square. \n" ); document.write( " By how many square centimeters did the area of the figure increase? \n" ); document.write( ": \n" ); document.write( "Let a = increase in length\r \n" ); document.write( "\n" ); document.write( "The square root of 144 is 12 cm, the original side of the square \n" ); document.write( "then \n" ); document.write( "(a+12) = the increased length \n" ); document.write( ": \n" ); document.write( "4(12) = 48 cm is the original perimeter \n" ); document.write( "; \n" ); document.write( "The equation for the new perimeter \n" ); document.write( "2(12) + 2(a+12) = 4(48) \n" ); document.write( "24 + 2a + 24 = 192 \n" ); document.write( "2a = 192 - 48 \n" ); document.write( "2a = 144 \n" ); document.write( "a = 144/2 \n" ); document.write( "a = 72 is the amt added to the length \n" ); document.write( "therefore \n" ); document.write( "72+12 = 84 is the new length \n" ); document.write( "and \n" ); document.write( "84*12 = 1008 sq/cm is the area \n" ); document.write( "1004 - 144 = 864 sq/cm increase in area when the perimeter is increased 4 times \n" ); document.write( " \n" ); document.write( " |